So, A0 has an area of 1 m2 and it’s halved for each next one in the series, giving A85 a surface area of 1/(285) m2 = 2.585×10-26 m2 = 0.02585 pm2.
The smallest atom is the hydrogen atom with a Van der Waals radius of 120 pm which gives it a surface area of 4×π×1202 pm2 = 180956 pm2 or just over 7 million times larger than the A85.
So, A0 has an area of 1 m2 and it’s halved for each next one in the series, giving A85 a surface area of 1/(285) m2 = 2.585×10-26 m2 = 0.02585 pm2.
The smallest atom is the hydrogen atom with a Van der Waals radius of 120 pm which gives it a surface area of 4×π×1202 pm2 = 180956 pm2 or just over 7 million times larger than the A85.