Edit: SOLVED. Thank you all for your incredible insights! All of you helped me improve my code and knowledge! Special thanks to @Quibblekrust@thelemmy.club who just NAILED it. :)
I’m playing around with Bash just to learn.
LIST=$(ls); for i in $LIST; do echo "I found one!"; done
The variable “i” could literally be anything, as long as it doesn’t have a special meaning for Bash, in which case I’d have to escape it, right? Anyway, my real question is: how does do (or rather the whole for-expression) know that “i” here means “for every line/item that ls outputs”? The above one liner works great and writes “I found one!” the number of times corresponding to the number of lines or items that ls outputs. But I would like to understand why it worked…
I’m a complete beginner at both Bash and C, but I understand some basic concepts.
Reading this part of the Bash manual for the third time today, I think I finally understood it better, thanks to this part in particular:
In other words, whatever follows
inis half expected to result in a list of words (items), each for which command is then executed. Beyond that, I guess I’d have to simply look at the logic behind for-expressions.Thanks!
Yeah it’s really not complicated, and it’s nearly plain English. For item in things, do action.