Edit: SOLVED. Thank you all for your incredible insights! All of you helped me improve my code and knowledge! Special thanks to @Quibblekrust@thelemmy.club who just NAILED it. :)
I’m playing around with Bash just to learn.
LIST=$(ls); for i in $LIST; do echo "I found one!"; done
The variable “i” could literally be anything, as long as it doesn’t have a special meaning for Bash, in which case I’d have to escape it, right? Anyway, my real question is: how does do (or rather the whole for-expression) know that “i” here means “for every line/item that ls outputs”? The above one liner works great and writes “I found one!” the number of times corresponding to the number of lines or items that ls outputs. But I would like to understand why it worked…
I’m a complete beginner at both Bash and C, but I understand some basic concepts.
Wouldn’t
for i in "$LIST";just result in a single loop iteration with$ibeing the entirety of$LIST?It would not, as @Quibblekrust@thelemmy.club explained in their comment (which I neglected to include in my explanation), Bash uses a special variable called
IFSwhen executing for loops like this.IFSstands for Input Field Separators, and is a list of one of each type of whitespace (tab, space, and newline), and uses these as separators automatically.So instead of taking that whole
lsoutput as one string of text, the for loop automatically separates it into an iterable list of strings using the newline separator.I’m pretty sure that IFS does not apply to quoted strings since word splitting happens before the quote removal (see Shell Expansion).
$ ( files=$(ls); IFS=$'\n' ; for x in $files; do echo $x; done ) file a.txt file b.txt plainfile.txt $ ( files=$(ls); IFS=$'\n' ; for x in "$files"; do echo $x; done ) file a.txt file b.txt plainfile.txtI didn’t realize that. Thanks for pointing that out!
Which makes it real fun when you have spaces in filenames!
Really you shouldn’t use ls as input to for. Use find -exec or something.