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Joined 2 years ago
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Cake day: April 13th, 2024

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  • A little I guess. When I had finally convinced my dad to try out a dual boot, and was trying to install it for him on his new Threadripper system, it failed. The platform support Threadripper wasn’t ready even though it had been out for at least a little while.

    But I don’t remember the details it has been around 8 years. Nowadays I know to confirm these things first, so in a sense it was my own mistaken assumption. But still it fits the question because at the time I was disappointed.









  • I am assuming everything other than the two ext4 partitions will have to go.

    Your /dev/sda5 the FAT32 mounted at /boot/efi has to stay too! That’s your EFI System Partition, it’s essential for the boot chain.

    What you can do is delete the “Microsoft” directory that’s on there, but definitely keep the one named after your distribution!







  • Best: Minecraft (bought at the Beta price), Counter Strike: Source, Counter Strike Global Offensive (I bought it before it became free), Rome Total War, Anno 1602, Age of Empires 2. I have hundreds of hours in all of these. Technically the last three were bought by my father originally, but I think I re-bought them all on digital platforms later.

    Worst: Tom Clancy Division 2 (because it’s shit and full of adverts), Monster Hunter World (because it never worked for me properly), Dragon Age 2 (just didn’t like the style of top down gameplay).






  • My pleasure!

    And I actually need to correct myself. When I woke up this night I suddenly remembered that I did the one thing that dBm is not great for in the example, and did it wrong.

    If you want to add up the power of five lasers you cannot add up their individual dBm numbers! Because that is already an addition operation when you do it on the absolute value scale! So adding them in the log scale would be like multiplying their powers, which makes no physical sense.

    So, again, the correct way:

    5 lasers of 4 mW or 6 dBm each, added up, actually comes out to 20 mW and then convert 10 * log10(20mW/1mW) = 13 dBm.

    Or alternatively we convert the factor of 5 into dB first, 10 * log10(5) = 7 dB, and the add that one to the 6 dBm to also arrive at 13 dBm.

    Then the rest of the example goes on like this:

    13 dBm - 12 dB + 15 dB = 16 dBm into the fiber

    16 dBm - 30 dB = -14 dBm at the end of the fiber

    -14 dBm + 20 dB - 12 dB = -6 dBm after the WSS

    and now split it for the 5 receivers, by

    • either subtracting the log of the factor 5 from above, -6 dBm - 7 dBm = -13 dBm per receiver, which is 10^(-13/10) = 0.05 mW.

    • or converting -6 dBm to 10^(-6/10) = 0.25 mW and then divide that absolute power by 5 to also arrive at 0.05 mW per receiver.