• psx_crab@lemmy.zip
    link
    fedilink
    English
    arrow-up
    2
    ·
    1 day ago

    Statistically yeah, who rolled first get the advantage, when you played like 100 round of it, then add up all the data and get the average, the first one to roll will on average ahead of everyone, but…we’re playing one game, the first one to roll will sometime roll low and the last to roll might roll double and get ahead, this is why i don’t think statistic really matter here because the amount of roll one game have is statistically insignificant to get the desired result. “The house always win” did not mean the house win every round, it just mean if the game goes for 100 round the house will come out on top statistically, and that applies here.

    • thebestaquaman@lemmy.world
      link
      fedilink
      arrow-up
      4
      ·
      1 day ago

      I think you’re misunderstanding something here?

      Let’s say you and a friend are playing: You can roll a dice or flip a coin to decide who goes first, and both of you have a 50/50 chance of going first, then you start playing. After the first throw, the player that starts will on average be ≈ 7 squares ahead of the second player, and can buy a property before the second player. Let’s call this a “7 square advantage”.

      Alternatively, you play one or more “warm up” rounds. When you get around the first round, the player that started will on average still have a 7 square advantage, and can still buy the same property before the second player. In fact, you can do as many “warmup rounds” as you like, and the player that started will retain their 7 square advantage whenever the first “real round” starts.

      The point is, this doesn’t become “more random” by playing “warmup rounds” the probability that any of the two players reaches a given square first is determined the instant the coin flip that decided who would go first landed.