• justme@lemmy.dbzer0.com
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    7 hours ago

    Might depend on the material. I have -3.5dpt on both sides and my glasses have half the width and glare. Or are those some random units again?

    • Redjard@reddthat.com
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      2 hours ago

      I assumed he’d estimated it based on how distorted the face appears behind the glasses. I do that all the time.

      At this angle it’s hard for me to do that, since I usually use the edges of the face to estimate it. negative glasses pull the line inwards, positive outwards. I can reliably tell when someone is wearing fake glasses (0 strength) for example, and probably estimate strength within 30% of the actual value.

      If the image was higher res maybe I could estimate this case too. Or this professional optometrist is just a lot better at it than I am.


      Strong negative glasses: (Note the faces contours in the glasses appearing well inside the faces contours around the glassed)

      Fake glasses:

      Positive glasses:


      PS: Searching for generic terms yields 100% fake glasses, so I took a specific person I remember having strong glasses for myopia.

      • justme@lemmy.dbzer0.com
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        2 hours ago

        Just looked in the mirror… Checks out! :)

        Thanks for the explanation. And yeah, on the op picture you can’t see any of that clearly, so he needs to have serious practice for that statement.

        • betterdeadthanreddit@lemmy.world
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          6 hours ago

          Going for “I see you” with a plausible but bullshit unit name but yours works too. Maybe they keep getting into accidents and landing in the ICU because of poor eyesight.

          • justme@lemmy.dbzer0.com
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            4 hours ago

            Aaah… So ist not the original prescription, rather the hit count. Like snipers carve lines in their rifle.

            Now it all comes together!